z^2-7z+16-2i=0

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Solution for z^2-7z+16-2i=0 equation:


Simplifying
z2 + -7z + 16 + -2i = 0

Reorder the terms:
16 + -2i + -7z + z2 = 0

Solving
16 + -2i + -7z + z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -2i + -7z + -16 + z2 = 0 + -16

Reorder the terms:
16 + -16 + -2i + -7z + z2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -2i + -7z + z2 = 0 + -16
-2i + -7z + z2 = 0 + -16

Combine like terms: 0 + -16 = -16
-2i + -7z + z2 = -16

Add '7z' to each side of the equation.
-2i + -7z + 7z + z2 = -16 + 7z

Combine like terms: -7z + 7z = 0
-2i + 0 + z2 = -16 + 7z
-2i + z2 = -16 + 7z

Add '-1z2' to each side of the equation.
-2i + z2 + -1z2 = -16 + 7z + -1z2

Combine like terms: z2 + -1z2 = 0
-2i + 0 = -16 + 7z + -1z2
-2i = -16 + 7z + -1z2

Divide each side by '-2'.
i = 8 + -3.5z + 0.5z2

Simplifying
i = 8 + -3.5z + 0.5z2

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